PatB
Stunt Coordinator
- Joined
- Feb 23, 2000
- Messages
- 166
I'm trying to help someone with this problem but I can't seem to break it, I'm not cheating or anything so it's all on the up and up.
12y^3-6y^2-42y+28=0
Solve for y.
(I don't know if this is the proper way to type this but for example the first part is 12 "y" cubed.)
12y^3-6y^2-42y+28=0
Solve for y.
(I don't know if this is the proper way to type this but for example the first part is 12 "y" cubed.)