Anthony Moore
Supporting Actor
- Joined
- Jul 12, 2001
- Messages
- 707
This has probably been discussed before, but I just have a probability question.
So Im sure everyone knows this roulette strategy:
Start with $10 on red or black. Lose? put down 20 on same color..lose? put down 40..80..160...320..640..
Win just one of those 7 spins in a row, and you pocket $10, and start the cycle over.
So lets say you pick red. You put all that money on red each time, having enough backup money to cover 6 losing spins.. As long as red comes up ONE time out of seven rolls, you win $10. If it doesnt, you lose everything
As long as red comes up once out of every spins, for 10 cycles in a row, thats $100.
To cover yourself for 7 spins it would cost you $2550. Its a lot of an investment, but how likely is it you will lose? Whats the probability that RED WILL or WONT come up just ONCE out of every seven spins?
So the downside is, even if you win, it will only be $10 on each cycle. But whats the odds it wont come up?
Just curious
So Im sure everyone knows this roulette strategy:
Start with $10 on red or black. Lose? put down 20 on same color..lose? put down 40..80..160...320..640..
Win just one of those 7 spins in a row, and you pocket $10, and start the cycle over.
So lets say you pick red. You put all that money on red each time, having enough backup money to cover 6 losing spins.. As long as red comes up ONE time out of seven rolls, you win $10. If it doesnt, you lose everything
As long as red comes up once out of every spins, for 10 cycles in a row, thats $100.
To cover yourself for 7 spins it would cost you $2550. Its a lot of an investment, but how likely is it you will lose? Whats the probability that RED WILL or WONT come up just ONCE out of every seven spins?
So the downside is, even if you win, it will only be $10 on each cycle. But whats the odds it wont come up?
Just curious