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Anders, I don't think that method would work either01 10 = [1/1=1]_________________ [0=0] 11 = [(1+0)/2=0.5=1]_________ [0+1=1] 22 = [(1+0+1)/3=0.66=1]______ [0+1+1=2] 14 = [(1+0+1+2)/4=1]_________ [0+1+1+2=4] 45 = [(1+0+1+2+4)/5=1.6=2]___ [0+1+1+2+1=5] 29 = [(1+0+1+2+4+5)/6=2.16=2]...

I'm in trouble. If I am indeed right, my method to get there may be flawed. My case for my answer is not able to support either the 1 or the 1 to 11 bracket. The second digit was derived by the sum of the digits in the number that preceded it. Example, the 5 in 45 was the sum of the 1 and 4...

29?