Why would a manufacturer use a 4-ohm driver in a speaker rated 8-ohm nominal?

Discussion in 'Archived Threads 2001-2004' started by John Pine, May 27, 2002.

  1. John Pine

    John Pine Supporting Actor

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  2. Walt N

    Walt N Second Unit

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    Two 4-ohm drivers wired in series = an 8-ohm load.
     
  3. John Pine

    John Pine Supporting Actor

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    Walt: OK, so if they used two 8 ohm drivers the nominal impedance would be 16?
     
  4. Fong

    Fong Stunt Coordinator

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    in series, yes
     
  5. Dustin B

    Dustin B Producer

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    And two 8 ohm drivers in parallel would be 4ohm nominal.
     
  6. John Pine

    John Pine Supporting Actor

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    Got it, thanks!
     
  7. Mark Fitzsimmons

    Mark Fitzsimmons Supporting Actor

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    Isn't it also possible to use two 4-ohm drivers and still have the final impedance 4 ohms?
     
  8. John Garcia

    John Garcia Executive Producer

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  9. Mark Fitzsimmons

    Mark Fitzsimmons Supporting Actor

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    Thats what I thought, thinking back upon component sets for car audio, two four ohm drivers and crossover equates a four ohm final impedence.
     
  10. John Pine

    John Pine Supporting Actor

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  11. Patrick Sun

    Patrick Sun Moderator
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    It has more to do with making speakers that are friendly to the amp, as most receivers are designed to provide a certain amount of current, and when a speaker present a low impedance load, the amps in receivers have a harder time providing the necessary current to the speaker, and you run the risk of clipping the amp, which will damage the speakers over the long run. So that's why commercial speaker designers shoot for a nominal 8 ohm impedance rating, but impedance is a function of frequency and there may be some part of the frequency spectrum that dip in the danger zone for low impedance. It all depends on the final circuit that the driver and crossover components create for the amp.
     
  12. John Pine

    John Pine Supporting Actor

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    Thanks for the insight Patrick!
     

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