steve jaros
Supporting Actor
What i want to know is - if a 16:9 TV is 40" (diagonal), how big would a 4:3 TV have to be to give me the same viewing surface area if i watched a widescreen DVD on it?
I know this is a geometry problem, but i'm too lazy to do the math. So does anyone have a chart or formula?
Thanks...
Plus, let me ask another question: Given that many high-end 4:3 TVs are being built with 16:9 modes (that allow you to unsqueeze the anamorphic DVD and get the extra resolution), what's the reason to buy a 16:9 instead of a 4:3 (given that i don't mind black bars?)...
I know this is a geometry problem, but i'm too lazy to do the math. So does anyone have a chart or formula?
Thanks...
Plus, let me ask another question: Given that many high-end 4:3 TVs are being built with 16:9 modes (that allow you to unsqueeze the anamorphic DVD and get the extra resolution), what's the reason to buy a 16:9 instead of a 4:3 (given that i don't mind black bars?)...