How to solving for volume of a cylinder

Discussion in 'Home Theater Projects' started by Shawn Shultzaberger, Oct 28, 2003.

1. Shawn Shultzaberger Supporting Actor

Joined:
Dec 2, 2000
Messages:
705
0
Trophy Points:
0
To solve for the volume of a cylinder, would the equation be:

3.14 x Radius squared x Height

So lets assume that I have a sonotube that is 16" in diameter and 32" tall. The radius is half of the diameter which would equal 8 inches therefore the equation would be:

3.14 x 8 squared x 32
3.14 x 64 x 32
= 6430.72 cu.in. or 3.72 cu.ft.??

I'm trying re-teach myself math by applying it to something that I enjoy.

2. Pete Mazz Supporting Actor

Joined:
May 17, 2000
Messages:
761
0
Trophy Points:
0
Yup!

Pete

3. Kyle Richardson Screenwriter

Joined:
Jan 1, 1998
Messages:
1,073
0
Trophy Points:
0

Yeah, I was surprised how much math is involved in speaker and subwoofer building when I first started.

4. Patrick Sun Studio Mogul

Joined:
Jun 30, 1999
Messages:
38,766
488
Trophy Points:
9,110
It's just geometry.

5. Dave Milne Supporting Actor

Joined:
Jul 2, 2001
Messages:
568
0
Trophy Points:
0
Just wait until you try some irregular, "curvy" enclosures. Solving finite integrals is a sure way to break a few pencils.

Hey, speaking of "speaker math", one time I botched the conversion from metric to english and used 28.3 (the conversion from liters to cubic feet) instead of 25.4 (the conversion from millimeters to inches). The speakers went together perfectly, but were 39% under target volume. DOH!