help with connecting two centre speakers

Discussion in 'Speakers' started by randyPar, Jun 17, 2005.

  1. randyPar

    randyPar Auditioning

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    Hello,
    In my new installation, because of the location of the screen and studds in the wall, i have to install two inwall speakers.

    My questions is how is the best way to hook them to the reciever. They are both 8ohm.
    1) do i just run two cables to the reciever and connect them in parrell?
    2) do i run one cable to the other speaker, connect them in parrell and run back to the reciever
    3) do i need some sort of components to do this?

    Thanks
    Randy
     
  2. John S

    John S Producer

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    You can run them in parallel.

    Which ever is easier, jumper one speaker to the other and then one connection back to the AVR, or run a connection from each speaker back to the AVR and parallel them there.

    Electrically there isn't any difference. Never tried in-walls just for the center. Let us know how you like that, I avoid it like the plague on the front L/R Mains. But on the center, it could work out.
     
  3. randyPar

    randyPar Auditioning

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    here is what someone else suggest
    what do you think
    ==============================================
    Well, your best bet is using another amp for the 2nd speaker. But, if you don't want to do that.

    #1 Connect the positive from your amp to one speaker.
    #2 Connect the negative from your amp to the other speaker.
    #3 Last, connect the negative of the #1 speaker to the positive of the #2 speaker.

    This will make your speakers run at 16ohms. It is much easyer on your amp.
     
  4. DaveHo

    DaveHo Supporting Actor

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    The correct answer depends on your amp. Will it handle a 4 ohm load? If not connect them in series:

    Amp+ -> S1+, S1- -> S2+, S2- -> Amp-

    If it will, connect them in parallel

    Amp+ -> S1&S2+, Amp- -> S1&S2-

    The safe bet is to connect them in series, although you will lose a bit of amp headroom that way. You could also use a speaker switcher which would protect against too low of an impedance.

    -Dave
     

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