I admit, my calculus is a bit fuzzy after not having it in over 8 years. But, since my girlfriend is taking a Calculus class I've found that I know a lot more about math and calculus then I thought I did. So far I've been able to answer every question she's had, cept for this one. When all else fails, turn to the Home Theater Forum collective for help.... so here goes. The problem ask for the values of a and b so that: Limit [(ax-b)^(1/2) - 3] / x = 2 (x->0) If I can get her the answer to this problem... she's promised me conjugal relations. Please help a brother out!