JJR512
Supporting Actor
- Joined
- Dec 11, 1999
- Messages
- 619
- Real Name
- Justin J. Rebbert
The OS doesn't have anything to do with fdisk, except for the fact that Microsoft wrote both, fdisk comes with the OS, and in the case of Windows 2000 and Windows XP, the only way to partition a hard drive (what fdisk does) is to put the OS's bootable CD-ROM and let it boot up your computer and start the Windows setup until it gets to the point where it asks you how you want your drives set up, with what partition sizes and what file system, etc.
You don't need an installed OS to do it, and as you said, you can disconnect that drive, and in fact, that is what I would do before doing something like this. Just to eliminate the chance that I accidentally partition the wrong drive!
Now I realize you're not using Windows 2000 or XP, so if you need a boot disk, check out www.bootdisk.com .
Wayne Bundrick, I'm not worried about losing the 8MB of space, I'm just curious to know why it's being reserved. Your explanation of partitions in 8MB increments doesn't really apply, because for one thing, it's not a SCSI drive, but mainly, if it had to be in 8MB increments, then either there would be no leftover space (total size of the drive was a multiple of 8MB), or else whatever space was left over would never be 8MB, but 7MB or less. In what I'm talking about, the reserved space is always exactly 8MB.
You don't need an installed OS to do it, and as you said, you can disconnect that drive, and in fact, that is what I would do before doing something like this. Just to eliminate the chance that I accidentally partition the wrong drive!
Now I realize you're not using Windows 2000 or XP, so if you need a boot disk, check out www.bootdisk.com .
Wayne Bundrick, I'm not worried about losing the 8MB of space, I'm just curious to know why it's being reserved. Your explanation of partitions in 8MB increments doesn't really apply, because for one thing, it's not a SCSI drive, but mainly, if it had to be in 8MB increments, then either there would be no leftover space (total size of the drive was a multiple of 8MB), or else whatever space was left over would never be 8MB, but 7MB or less. In what I'm talking about, the reserved space is always exactly 8MB.